Accept the Float Value and Precision Value and Print the Float Value According to the Precision Given

Question:

Accept the Float Value and Precision Value and Print the Float Value According to the  Precision Given.

TestCase InputExpected Output

15.87 6 15.870000

---

12.3 312.300

Answer:

#include<stdio.h>
int main()
{
  float num;
  int precision;
  scanf("%f %d",&num,&precision);
  printf("%.*f",num,precision);
  return 0;
}


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